Three sets of english, mathematics, and physics books have to be stacked in such a way that all the books are stored topics wise and the height of each store is the same. The number of english books is 96, mathematics books is 240, and physics books is 336. Assuming the books are of the same thickness, determine the total number of stacks of physics books.
Right and written answer pls
Answers
Answer:
A shopkeeper bought 50 English books at the cost of rupees 2000 per 25 books and 75 Mathematics books at the cost of rupees 1500 per 15 books. Find:
(a) The cost price of the English books.
(b) The cost price of the Mathematics books.
(c) The cost price of all English and Mathematics books.
(d) If he sold the English books at rupees 95 per book, find his profit in English books.
Answer:
Three sets of physics chemistry and mathematics books have to be stacked.
Bur all the books are stored topic wise and the number of books in each stack is same.
Number of Physics books = 192
Number of Chemistry books = 240
Number of Mathematics books = 168
We will calculate the Highest Common Factor (HCF) of the numbers.
Factors of 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3
Factors of 240 = 2 × 2 × 2 × 2 × 3 × 5
Factors of 168 = 2 × 2 × 2 × 3 × 7
Common factors = 2 × 2 × 2 × 3
HCF = 24
In each stack there are 24 books. Therefore, the number of stack of each subject would be
No. of stacks of Physics books = {192}{24}
= 8
No. of stacks of Chemistry books = {240}/{24}
= 10
No. of stacks of Mathematics books = {168}/{24}
= 7
The number of stacks of physics = 8, Chemistry = 10 and mathematics = 7