Math, asked by veerakrishnarep83gam, 1 year ago

three sets of physics, chemistry and mathematics books have to be stacked in such a way that all the books are stored topic wise and the number of books in each stack is the same.the number of phusics books is 192,the number of chemistry books is 240 and the number of mathematics books os 168.determine the number of stacks of physics ,chemistry and mathematics books.

Answers

Answered by vbhai97979
205

Answer:

Three sets of physics chemistry and mathematics books have to be stacked.

Bur all the books are stored topic wise and the number of books in each stack is same.

Number of Physics books = 192

Number of Chemistry books = 240

Number of Mathematics books = 168

We will calculate the Highest Common Factor (HCF) of the numbers.

Factors of 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3

Factors of 240 = 2 × 2 × 2 × 2 × 3 × 5

Factors of 168 = 2 × 2 × 2 × 3 × 7

Common factors = 2 × 2 × 2 × 3

HCF = 24

In each stack there are 24 books. Therefore, the number of stack of each subject would be

No. of stacks of Physics books = {192}{24}

= 8

No. of stacks of Chemistry books = {240}/{24}

= 10

No. of stacks of Mathematics books = {168}/{24}

= 7

The number of stacks of physics = 8, Chemistry = 10 and mathematics = 7

Step-by-step explanation:

BTS ARMY

Answered by tanvigupta426
3

Answer:

The number of stacks of physics = 8, Chemistry = 10 and

Mathematics = 7.

Step-by-step explanation:

Given:

Three sets of physics, chemistry, and mathematics books have to be stacked in such a way that all the books are stored topic-wise and the number of books in each stack exists the same.  

Number of Physics books = 192

Number of Chemistry books = 240

Number of Mathematics books = 168

Step 1

We will calculate the Highest Common Factor (HCF) of the numbers.

Factors of 192= 2 * 2 * 2 * 2 * 2 * 2 * 3

Factors of 240= 2 * 2 * 2 * 2 * 3 * 5

Factors of 168 = 2 * 2 * 2*  3* 7

Common factors = 2 * 2 * 2 * 3

HCF = 24

In each stack, there are 24 books.

Step 2

The number of a stack of each subject would be

Number of stacks of Physics books = {192}{24}

= 8

Number of stacks of Chemistry books = {240}/{24}

= 10

Number of stacks of Mathematics books = {168}/{24}

= 7

Therefore, the number of stacks of physics = 8,

Chemistry = 10 and mathematics = 7

#SPJ2

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