Math, asked by prasadbhandare0112, 7 months ago


Three shops A, B and sold tarsin January, February and March The total number of cars sold in this three-month period by A, B and were 400, 320 and
500 respectively. Both A and C sold the same number of cars in January. The number of cars sold by A and C in March was also the same. A sold 120 cars in
February which was half of the number of cars sold by C in March. Both A and B sold exactly the same number of cars in February. The ratio of the number of
cars sold by B in January, and March was 1:4.
What was the ratio of the total number of cars sold in January, February and March by the three shops?
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Answered by amitnrw
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Given : Three shops A, B and C sold cars  in January, February and March

The total number of cars sold in this three-month period by A, B and C were 400, 320 and  500 respectively

To Find :  ratio of the total number of cars sold in January, February and March by the three shops

Solution :

Both A and C sold the same number of cars in January.

= J  

The number of cars sold by A and C in March was also the same.

= M

Car Sold by B in March = 500 - 2M

A sold 120 cars in  February which was half of the number of cars sold by C

=> 120 = M/2

=> M = 240  

car sold by  A and C in March = 240

Both A and B sold exactly the same number of cars in February

A & B in February = 120

A sold  = J  + 120  + 240  = 400

=> J = 40

C sold  = 40 + 240  + in Feb = 500

=> C sold   in Feb = 220

B sold  x + 4x  + 120  = 320

=> 5x = 200

=> x = 40

B sold in Jan  = 40  , Feb = 120  Mar = 160

           A      B      C

JAN = 40 + 40 + 40  =   120

FEB = 120 + 120 + 220  = 460

MAR  240 + 160 + 240 =  640

         400    320    500

120 : 460 : 640

= 6 : 23 : 32

6 : 23 : 32  is the ratio

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3:5:8 in the ratio ayhahahhaaua

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