Question

three side of a triangular field are of length 15 metre 20 metre and 25 metre respectively find the cost of showing seed in the field at the rate of ₹50 per square​

Answer 1

Answer:

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Three sides of a triangular field are of length 15 m, 20 m and 25 m long, respectively. Find the cost of sowing seeds in the field at the rate of RS. 5 per Sq m.

A) 750

B) 150

C) 300

D) 600

Correct Answer:

A) 750

Description for Correct answer:

Since,AC2=AB2+BC2

=> (25)2=(15)2+(20)2

=> 625=225+400

=> 625 = 625

So, the triangular field is right angled at B

Area of the field = 12×AB×BC

= 12×15×20

=150m2

So, the cost of sowing seed is RS. 5 per sq m

Cost of sowing seed for

150m2=150×5

= RS. 750

Answer 2

$\large{\underline{\underline{\textsf{\maltese\:{\red{Given :-}}}}}}$

$\sf{Sides\: of\: triangular \:filed\: are\: 15 \:m , \:20 \:m\: and \:25 \:m}$

$\large{\underline{\underline{\textsf{\maltese\:{\red{To\:Find}}}}}}$

The cost of showing seed in the field at the rate of ₹50 per square

$\large{\underline{\underline{\textsf{\maltese\:{\red{Solution:}}}}}}$

$\sf{Area\: of\: triangle = \sqrt{ s (s - a)(s-b) (s-c)}}$

$\sf{Where, value \:of\: "s" = \dfrac{a + b+c }{2} }$

$\sf{Substitute \:the\: value:}$

$\sf{ \dfrac{15 + 20+25 }{2} }$

$\sf{s= \dfrac{15+20+25}{2}}$

$\sf{s=30}$

$\sf{Area\: of \:triangle = \sqrt{30(30-15)(30-20)(30-25)} }$

$\sf{Area\: of\: triangle = 150 m^2}$

$\sf{Cost \:of \:sowing\: 1 m^2 = ₹5}$

$\sf{Cost \:of\: sowing\: 150 m^2 = 5 \times 150}$

$\sf={₹(7505×150)}$

$\sf{=₹750}$

$\sf{Hence\: the\: cost\: of\: sowing \:seeds\: in\: the\: field \:at \:the}$ $\sf{rate\: of ₹ \:5 per\: m^2\: is\: ₹750}$