Question

Three sides of a triangle ABC are given below. State whether the triangle is a right angled triangle .If, so then find the right angle. AB =√6 cm, BC = (√2+1)cm and AC = (√2-1)cm.​

Answer 1

Answer:

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Answer 2

Given:-

• Three sides of a triangle ABC.
• Sides are AB = √6 cm,BC = (√2+1)cm and AC = (√2-1)cm.

To Find:-

• State whether the triangle is a right angled triangle.

Solution:-

By Pythagoras theorem,

$\sf ( {bc}^{2} ) = ( {ab}^{2} ) + ( {ac}^{2} )$

Now put the values

$\sf \implies \: {( \sqrt{2} + 1)}^{2} = {( \sqrt{6}) }^{2} + {( \sqrt{2} + 1)}^{2} \\ \\ \sf \implies \: 2 + 1 = 6 + 2 + 1 \\ \\ \sf \implies \:3 = 9$

Hence,here we can see that LHS is not equal to RHS so the triangle is not a right angled.