Question

Three sides of a triangle are 2x^2+3x+1,x^2+7,and 3x^2-2x+3.Find the perimeter of the triangle when x=-3.

Answer 1

perimeter = 2x^2+3x+1+x^2+7+3x^2-2x+3
putting value of x= -3
2(-3)(-3)+3(-3)+1+(-3)(-3)+7+3(-3)(-3)-2(-3)+3
18-9+1+9+7+27+6+3
62 units

Answer 2

sides are 2x²+3x+1, x²+7 and 3x²-2x+3

and

x= -3

perimeter of triangle= sum of all three sides

                =2x²+3x+1+x²+7 + 3x²-2x+3                              

               =2(-3)² + 3(-3)+1 +(-3)²+7+3(-3)² - 2(-3) +3       (∵ x= -3)

               =18 -9 + 1 +9+7+27+6+3

               =9+10+34+9

               =19+43

               =62 units