three sides of a triangle measure {5x-2} units,{4x+5} units and 3x units find the measure of the sides if its perimeter is 171 units
raoatchut191:
thnx
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Answered by
5
perimeter of triangle = a+ b+ c =171
= 5x-2+4x+5+3x=171
= 12x + 3 = 171
= 12x=168
= x=14
a=68,b=61,c=42
= 5x-2+4x+5+3x=171
= 12x + 3 = 171
= 12x=168
= x=14
a=68,b=61,c=42
Answered by
5
perimeter of a triangle=a+b+c=171
5x-2+4x+5+3x=171
12x+3=171
12x=168
x=14
so
a=5x-2=5.14-2=70-2=68
b=4x+5=4.14+5=56+5=61
c=3x=3.14=42
5x-2+4x+5+3x=171
12x+3=171
12x=168
x=14
so
a=5x-2=5.14-2=70-2=68
b=4x+5=4.14+5=56+5=61
c=3x=3.14=42
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