Three sides of right triangle are in AP find the three possible minimum sides.
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0
Answer:
sorry i didn't understand this question .
can you explain me so that i will surelly answer..
thankyou
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mark me as brainleist pls ..
rkcomp31:
Friend All matter is of understanding .Doctor charges Rs 100 to 200 For medicines but charge of tests may be 2000, to 10000 or more...,Try do diagnosis or take help ( Hind three sides are in AP may be: a-d,a and a+d),Now a+d is hypotenuse .Now apply Pythagoras theorem,then simple)
for simple take d=1
oh . ok
IT COULD BE 3 OR 4 OR 5 UNITS ..
THANKYOU
ok then do correction if possible
Answered by
1
Step-by-step explanation:
Given:-
Three sides of right triangle are in AP.
To find:-
AP find the three possible minimum sides.
Solution:-
Let the sides of the right triangle which are in the AP are a-d,a,a+d respectively.
Since they are the sides of right triangle
(a+d)²=(a-d)²+a²
=>a²+2ad+d²=a²-2ad+d²+a²
=>2ad=-2ad+a²
=>a²=2ad+2ad
=>a²=4ad
=>a²/a=4d
=>a=4d
now the sides are
a-d=4d-d=3d
a=4d
a+d=4d+d=5d
the three sides are 3d,4d,5d
now for minimum values,put d=1 then we get
3units ,4units,5units
Answer:-
the three possible minimum sides are
3 units,4 units and 5 units
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