three similar charges of magnitude q each are placed at corners of an equilateral triangle ABC of a side a. find the net force acting on charge placed at C.
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F net = 2F cos Ф/2
In an equilateral triangle, all angles are 60°. So, Ф=60°
F net = 2 x kq² / a² cos 60/2
F net = 2 x kq² / a² x √3/2 = √3kq²/a²
In an equilateral triangle, all angles are 60°. So, Ф=60°
F net = 2 x kq² / a² cos 60/2
F net = 2 x kq² / a² x √3/2 = √3kq²/a²
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