Question

Three sisters share some money. The oldest gets 9/11 of the money. The next girl gets 7/12 of the remainder. What fraction of the money does the youngest girl get?

Answer 1

Answer:

The youngest sister got $\frac{5}{66}$ of the money.

Step-by-step explanation:

Let the original amount be x.

The oldest get $\frac{9}{11}x$.

The next sister got $\frac{7}{12}$ of the remaining, i.e. $\frac{7}{12}\times (x-\frac{9}{11}x)=\frac{7}{12}\times \frac{2}{11}x=\frac{14}{132}x$

The remaining amount is:

$Remaining=x-\frac{9}{11}x-\frac{14}{132}x\\=\frac{132x-108x-14x}{132}\\=\frac{10}{132}x\\ =\frac{5}{66}x$

Thus, the youngest sister got $\frac{5}{66}$ of the money.