Question

Three solid metal cubes with edges 6cm, 8cm and 10cm respectively are melted together  and formed a single cube. The edge of the new cube so formed is​

Answer 1

Answer

volume remains same so

volume of new cube = v1+v2+v3

= 6^3+8^3+10^3

=216+512+1000

=1728

now volume of new cube = a^3= 1728

edge of new cube = a= cuberoot of 1728

a= 12

therefore surface area of new cube = 6 a^2

=6×12^2

=6×12×12

=864 square cm

Answer 2

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Three solid metal cubes with edges 6cm, 8cm and 10cm respectively are melted together  and formed a single cube. The edge of the new cube so formed is ?

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volume remains same so

volume of new cube = v1+v2+v3

⟹ 6^3+8^3+10^3

⟹216+512+1000=

⟹1728

now volume of new cube = a^3= 1728

edge of new cube = a= cuberoot of 1728

a= 12

therefore surface area of new cube = 6 a^2

=6×12^2

6×12×12

=864 square cm

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