Three solid metallic balls of radii 3 cm, 4 cm and 5 cm are melted and moulded into a single solid ball. The radius of the new ball is :
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volume of the moulded ball = sum of the volumes of three balls
let the radii of three balls r1, r2, r3 respectively and of the moulded ball R
since the balls are spherical therefore there volume will be =4/3 pi r^3
according to question
4/3 pi R^3 = 4/3 pi (r1^3+r2^3+r3^3)
4/3 pi will be cancelled
R^3=27+64+125
R= cube root of 216
6cm
hence the radius of the resulting ball is 6cm
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