Question

three solid metallic spheres of radii 3cm,4cm,5cm are melted together and recast into a cone of height 24cm then the radius of the cone is

Answer 1

Hola Friend ✋✋✋

Volume of 3 small spheres = volume of cone

Volume of 3 spheres

$= \frac{4}{3} \times \pi \times ( {3}^{3} + {4}^{3} + {5}^{3} ) \\ \\ = \frac{4}{3} \times \pi \times 216 \\ \\ = 288\pi$

Volume of cone

$= \frac{1}{3} \times \pi \times {r}^{2} \times 24 \\ \\ = 8\pi \: {r}^{2}$

Therefore...

288π = 8πr²

r² = 36

r = 6 cm

Hope it helps

Answer 2

volume of sphere{1}=4/3pi*[r]3+volume of sphere[2]+volume of sphere[3]=volume of cone 1/3pi*[r]2*h 
substitute the values and you get the answer