Math, asked by treemango67, 1 year ago

THREE SOLID SPHERE WHOSE DIAMETERS ARE 2CM, 12CM,16CM RESPECTIVELY ARE MELTED INTO A SINHLE SPHERE .FIND THE RADIUS OF THE SOLID SPHERE.

Answers

Answered by vdm
1
HEY BUDDY ........
HERE IS UR ANSWER........

ACCORDING TO THE PROBLEM ,

THREE SOLID ARE MELTED , SO, THE VOLUME OF THE NEW SOLID WILL BE EQUAL TO THE VOLUME OF 3 SPHERES

THEREFORE ,.
VOLUME OF 3 SOLID SPHERE = 4/3πr^3 + 4/3πr^3 + 4/3 πr^3 = 4/3π(r^3) = 4/3×22/7×(2/2+12/2+16/2) = 4/3×22/7(1+6+8)
= 4/3×22/7×(15)^3 = 4714.28572 cm^3

SO, VOLUME OF NEW SOLID SPHERE = 4/3πR^3 = 4714.28572 cm^3
SO, R = ✓4714.28572×3/4 = 59.46 cm

THEREFORE , RADIUS OF NEW SOLID SPHERE IS 60 approx cm .

HOPE U UNDERSTAND BRO ✨✨

AND BRO FOLLOW ME :)

treemango67: answer is 9
treemango67: i got it in rd sharma
treemango67: but thank you
vdm: okkkAND SORRY I HAVE DONE A MISTAKE
vdm: I HAVE TAKEN THE RADIUS THE SAME AND ADDED IT SO IT WILL COME WRONG
vdm: HEY BUDDY FOLLOW ME
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