THREE SOLID SPHERE WHOSE DIAMETERS ARE 2CM, 12CM,16CM RESPECTIVELY ARE MELTED INTO A SINHLE SPHERE .FIND THE RADIUS OF THE SOLID SPHERE.
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HEY BUDDY ........
HERE IS UR ANSWER........
ACCORDING TO THE PROBLEM ,
THREE SOLID ARE MELTED , SO, THE VOLUME OF THE NEW SOLID WILL BE EQUAL TO THE VOLUME OF 3 SPHERES
THEREFORE ,.
VOLUME OF 3 SOLID SPHERE = 4/3πr^3 + 4/3πr^3 + 4/3 πr^3 = 4/3π(r^3) = 4/3×22/7×(2/2+12/2+16/2) = 4/3×22/7(1+6+8)
= 4/3×22/7×(15)^3 = 4714.28572 cm^3
SO, VOLUME OF NEW SOLID SPHERE = 4/3πR^3 = 4714.28572 cm^3
SO, R = ✓4714.28572×3/4 = 59.46 cm
THEREFORE , RADIUS OF NEW SOLID SPHERE IS 60 approx cm .
HOPE U UNDERSTAND BRO ✨✨
AND BRO FOLLOW ME :)
HERE IS UR ANSWER........
ACCORDING TO THE PROBLEM ,
THREE SOLID ARE MELTED , SO, THE VOLUME OF THE NEW SOLID WILL BE EQUAL TO THE VOLUME OF 3 SPHERES
THEREFORE ,.
VOLUME OF 3 SOLID SPHERE = 4/3πr^3 + 4/3πr^3 + 4/3 πr^3 = 4/3π(r^3) = 4/3×22/7×(2/2+12/2+16/2) = 4/3×22/7(1+6+8)
= 4/3×22/7×(15)^3 = 4714.28572 cm^3
SO, VOLUME OF NEW SOLID SPHERE = 4/3πR^3 = 4714.28572 cm^3
SO, R = ✓4714.28572×3/4 = 59.46 cm
THEREFORE , RADIUS OF NEW SOLID SPHERE IS 60 approx cm .
HOPE U UNDERSTAND BRO ✨✨
AND BRO FOLLOW ME :)
treemango67:
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