Three solid spheres each of mass m and radius l are placed at the corner of an equilateral triangle of side 2l the moment of inertia of the system about an axis along one of side of the triangle is.....
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moment of inertia application
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The moment of inertia of the system about an axis along the side of triangle is 21/5Ml²
Total number of spheres = 3 (Given)
Mass of the spheres = m (Given)
Side of the Triangle = 2l (Given)
Moment of inertia of sphere from axis = 2/5Ml²
Therefore,
I1 - 2/5Ml² = I2
I3 = 2/5Ml² + Mx² = 2/5Ml² + 3Ml²
= 17/5Ml2²
Therefore,
I = I1 + I2 + I3
= 2/5Ml² + 17/5Ml²
= 21/5Ml²
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