three solid sphers of radius 3cm, 4cm, and 5cm are melted and recasted into a solid sphere. What will be the percentage decrease in the surface area?
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Answer:
helping hand!!!!!
Step-by-step explanation:
According to question.
43 π( 33)+43 π (43 )+43 π (53 )+43 π( r3 )
27+64+125 = r3
216 = r3
r = 6
The surface area of all three spheres
=4 π(32)+ 4 π(42)+ 4 π(52)
=4 π * 9 + 4 π * 16 + 4 π * 25
= 200 π
The surface area of new sphere = 4π62
= 144π
Required decrease =
= 28%
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