Chemistry, asked by wisteria903, 9 months ago

Three solid substance A B C have melting point 25° 147° 102°respectively. Arrange the following substance in order of their decreasing force of attraction.

Answers

Answered by Ieaticyhot
1

Answer:

C B A

Explanation:

Force of attraction is higher in solids, decreases in liquid and is the lowest in gaseous. Briefly, force of attraction will be higher in solids than others.

At 102°, C substance will be the only one of the three which is solid. Thus, it's force of attraction will be higher than B or A.

Similarly, at 147°, force of attraction will be higher in B than A.

At last, the force of attraction will be the least in A since it has the lowest melting point.

This concludes my answer : From the highest force of attraction to the lowest, it goes like this ── C B A

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Answered by arish1234567890
0

Answer:

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