Question

→ Three Solutions
X, Y, Z of HCL are mixed
to produce 100 ml solution the
molarities of X,Y,Z are 0.07m, 0.12M
and 0.15M respectively What should
the volumes of X, Y, Z.​

Answer 1

Answer:

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Explanation:

1. The amount of HCl in the resulting solution is the following:

(HCl) = (HCl)

(solition)

Consequently

(HCl) = (HCl) · (solition) = 100

1000 · 0.1

= 0.01

2. The volume of HCl in every solution is marked with x, y and z. We can write the

equation:

Σ(HCl) = (HCl) + (HCl) + (HCl) = + + = 0.1

Or

+ + = 0.1

3. Then we write the formula for total amount of HCl:

Σ(HCl) = (HCl) + (HCl) + (HCl) = Σ(HCl) · Σ(HCl)

= (HCl) · (HCl) + (HCl) · (HCl) + (HCl) · (HCl)

= 0.07 + 0.12 + 0.15 = 0.01

Or

0.07 + 0.12 + 0.15 = 0.01

Or

7 + 12 + 15 = 1

4. The elimination of variable x it can be expressed by y, that is the solution Z is

substituted by Y by way of coefficient expressed by ratio of respective molarities:

(HCl)

(HCl) = 1.25

Consequently,

= 1.25

5. The set of equations can be composed:

� + + = 0.1

7 + 12 + 15 = 1

If = 1.25, then

� + + 1.25 = 0.1

7 + 12 + 18.75 = 1

Then

�

+ 2.25 = 0.1

7 + 30.75 = 1

�

= 0.1 − 2.25

7 + 30.75 = 1

Then

7 · (0.1 − 2.25) + 30.75 = 1

0.7 − 15.75 + 30.75 = 1

15 = 0.3

= 0.02

= 1.25 = 0.025

= 0.1 − − = 0.1 − 0.02 − 0.025 = 0.055

6. The volumes of solutions X, Y, Z are:

(HCl) = 0.055 = 55

(HCl) = 0.025 = 25

(HCl) = 0.020 = 20

Answer: The volumes of X, Y, Z solutions are 0.055 L, 0.025 L and 0.020 L respectively.