Question

three spheres of mass M and radius R are kept in touch such that their centres form an equilateral triangle the M.I of system about a median of triangle is​

Answer 1

The moment of inertia of the system about an axis along the side of triangle is 21/5Ml²

Total number of spheres = 3 (Given)

Mass of the spheres = m (Given)

Side of the Triangle = 2l (Given)

Moment of inertia of sphere from axis = 2/5Ml²

Therefore,

I1 - 2/5Ml² = I2

I3 = 2/5Ml² + Mx² = 2/5Ml² + 3Ml²  

= 17/5Ml2²

Therefore,  

I = I1 + I2 + I3  

= 2/5Ml² + 17/5Ml²

= 21/5Ml²

Answer 2

Explanation:

hi Sanjan jeevika, sorry to tell u that ur answer is completely wrong

ANSWER:

I=I1+I2+I3

I=2/5Mr²+2×7/5Mr²

I=16/5Mr²