three spheres of radii 3cm 4cm and 5cm are melted to recast a single sphere find the radius of the sphere hence find its surface area
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total volume of the spheres = volume of the new sphere = 7241.14 cm^3
{ 4/3 (pie x r^3 }
radius of new sphere = 12
thus, TSA of the new sphere = 4 x pie x r^2 = 1810.1 cm^2
{ 4/3 (pie x r^3 }
radius of new sphere = 12
thus, TSA of the new sphere = 4 x pie x r^2 = 1810.1 cm^2
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