Question

*Three squares are based on the sides of a right angled triangle. The area of the two smaller ones are 144 sq. cm and 256 sq. cm. What is the area of the third one?*

1️⃣ 625 sq cm
2️⃣ 361 sq cm
3️⃣ 400 sq cm
4️⃣ 900 sq cm
​

Answer 1

Step-by-step explanation:

$\huge \pink{ \bull} \: \: \underline \boldsymbol{ \blue{Solution:-}}$

Given:

• Based on the sides of a right angle triangle.
• Area of the two smaller ones are 144 cm² and 256 cm².

To Find:

• Area of the Third side .

Answer:

Let the first smaller side be 144 cm² and second smaller side be 256 cm²

In Right angled triangle bigger side will be Hypotenuse side.

By Pythagoras theorem:

Let the hypotenuse side be x.

$: \sf \implies \red{x = \sqrt{ {(144)}^{2} + {(256)}^{2} } }$

$: \sf \implies \red{x =144 + 256}$

$: \sf \implies \red{x =400 \: c {m}^{2} }$

•°• The third side be option (3) 400 cm² !!

#Make it easy ◉‿◉

Answer 2

Step-by-step explanation:

Step-by-step explanation:

\huge \pink{ \bull} \: \: \underline \boldsymbol{ \blue{Solution:-}}∙

Solution:−

Given:

Based on the sides of a right angle triangle.

Area of the two smaller ones are 144 cm² and 256 cm².

To Find:

Area of the Third side .

Answer:

Let the first smaller side be 144 cm² and second smaller side be 256 cm²

In Right angled triangle bigger side will be Hypotenuse side.

By Pythagoras theorem:

Let the hypotenuse side be x.

: \sf \implies \red{x = \sqrt{ {(144)}^{2} + {(256)}^{2} } }:⟹x=

(144)

2

+(256)

2

: \sf \implies \red{x =144 + 256}:⟹x=144+256

: \sf \implies \red{x =400 \: c {m}^{2} }:⟹x=400cm

2

•°• The third side be option (3) 400 cm² !!

#Make it easy ◉‿◉