Math, asked by triptikumari46778, 7 months ago

Three squares P, Q,and R are such that the perimeter of P is 2/3 the pwrimeter of Q, and the perimeter of Q is 2/3 the perimeter of R . if the area of P is 16 sq. units, what is the area of R?​

Answers

Answered by singhsardar9105
0

Answer:

36 sq. units

Step-by-step explanation:

perimeter of P = 2/3 of Q

But Perimeter of P = 16 sq. units

Therefore, 2/3 ×Q= 16 sq.units

Perimeter Of Q= 16×3/2

= 24 sq. units

Perimeter Of Q=2/3 of R

But Perimeter Of Q= 24sq. units

Hence Perimeter Of R = 24×3/ 2

= 36 sq.units

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