Three squares P, Q,and R are such that the perimeter of P is 2/3 the pwrimeter of Q, and the perimeter of Q is 2/3 the perimeter of R . if the area of P is 16 sq. units, what is the area of R?
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Answer:
36 sq. units
Step-by-step explanation:
perimeter of P = 2/3 of Q
But Perimeter of P = 16 sq. units
Therefore, 2/3 ×Q= 16 sq.units
Perimeter Of Q= 16×3/2
= 24 sq. units
Perimeter Of Q=2/3 of R
But Perimeter Of Q= 24sq. units
Hence Perimeter Of R = 24×3/ 2
= 36 sq.units
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