Three squares P,Q and R are such that the perimeter of P is the perimeter of Q, and
the perimeter of Q is 23 the perimeter of R. If the area of P is 16 sq. Units, what is the area of
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Solution:
(a) Perimeter of square = 4 x side
= 4 x 25 = 100 cm
(b) Perimeter of rectangle = 2 x (length + breadth)
= 2 x (40 + 10)
= 2 x 50 = 100 cm
(c) Perimeter of rectangle = 2 x (length + breadth)
= 2 x (30 + 20)
= 2 x 50 = 100 cm
(d)Perimeter of triangle = Sum of all sides
= 30 cm + 30 cm + 40 cm = 100 cm
Thus, all the figures have same perimeter.
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