THREE STUDENTS A,B AND C, WALKING ON THE STREET WITNESSED A CAR VIOLATING A TRAFFIC REGULATION.NO ONE REMEMBERED THE LICENCE NUMBER,BUT EACH GOT SOME PERTICULAR ASPECT OF IT.A REMEMBERED THAT THE FIRST TWO DIGITS ARE EQUAL, B NOTED THAT THE LAST TWO DIGITS ARE ALSO EQUAL,AND C SAID THAT IT IS A FOUR-DIGIT NUMBER AND IS A PERFECT SQUARE.WHAT IS THE LICENCE NUMBER OF THE CAR?
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Given:
A REMEMBERED THAT THE FIRST TWO DIGITS ARE EQUAL,
B NOTED THAT THE LAST TWO DIGITS ARE ALSO EQUAL,AND
C SAID THAT IT IS A FOUR-DIGIT NUMBER AND IS A PERFECT SQUARE.
To find:
WHAT IS THE LICENCE NUMBER OF THE CAR?
Solution:
From given we can note that,
The first two and last two digits are same.
Licence number of the car is a 4 digit number.
Therefore, we have,
7744 = 88 × 88
7744 has first two and last two digits are same and is even a perfect square of 88.
⇒ 88² = 7744
Therefore, 7744 is the license number of the car.
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