Question

Three tankers contain 385litre 415litre and 505litre of petrol respectively. Find the minimum capacity of a container that can measure the petrol of the three tankers exact number of times.

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Answer 1

Min. capacity of required container=HCF(385,415,505)

385 = 5×7×11

415 = 5×83

505 = 5×101

HCF = 5

.°. Required container = 5L.