Question

Three tankers contain 403 liters 434 liters 465liters of diesel find the minimum capacity of a container that can three containers extact number of times​

Answer 1

Answer:

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Answer 2

Answer:

Amount of diesel present in the

first tank = 403 litres

second tank = 434 litres

third tank = 465 litres

The maximum capacity of container = H.C.F. of (403, 434, 465)

∴ H.C.F of (403, 434, 465) = 31

Therefore, 31 litres of the container is required to measure the quantity.