Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times .
Answers
Answer:
The maximum capacity of container = H.C.F. of (403, 434, 465)
Factors of 403 = 13 x 31
Factors of 434 = 2 x 7 x 31
Factors of 465 = 3 x 5 x 31
H.C.F = 31
Therefore, 31 liters of container is required to measure the quantity.
ANSWER : -
31 LITRES
EXPLAINATION:-
HCF (403,434,465)
13|403. 2|434. 3|465
31|31. 7|217 5|155
| 1. 31|31. 31|31.
| 1. | 1.
403 = 13 × [31]. here the common
434 = 2×7×[31]. Number is 31
465= 3×5×[31]. *HCF = 31*. ANSWER
= 31 LITRES
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