Math, asked by rhymee, 9 months ago

Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of three containers exact number of times.
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Answers

Answered by rchhalaria
0

Step-by-step explanation:

The maximum capacity of container = H.C.F. of (403, 434, 465)

Factors of 403 = 13 x 31

Factors of 434 = 2 x 7 x 31

Factors of 465 = 3 x 5 x 31

H.C.F = 31

Therefore, 31 liters of container is required to measure the quantity.

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Answered by niranjan1739
1

Step-by-step explanation:

Given: Three tankers contain 403 litres,434 litres and 465 litres of diesel.

We need to find: Maximum measuring capacity of the container to measure the three tankers.

Since measuring capacity is smaller than 403,434,465

Maximum measuring capacity=HCF of 403,434,465

Factors of 403=13×31

Factors of 434=7×2×31

Factors of 465=3×5×31

So,HCF=31

∴ Maximum measuring capacity=31litres

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