Three taps A, B and C can fill a tank in 10, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, find the time taken to fill the tank.
Answers
Answered by
0
Answer:
Step-by-step explanation:
(A+B)'s hour's work=(
12
1
+
15
1
)=
60
9
=
20
3
.
(A+C)'s hour's work =(
12
1
+
20
1
)=
60
8
=
15
2
.
Part filled in 2hrs =(
20
3
+
15
2
)=
60
17
.
Part filled in 6hrs=(3×
60
17
)=
20
17
.
Remaining part =(1−
20
17
)=
20
3
.
Noe, it is turn of A and B and
20
3
part is filled by A and B in 1 hour.
∴ Total time taken to fill the tank =(6+1)hrs =7hrs.
Answered by
0
Answer:
1/10
1/15
1/20
Hope you understand
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