Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
A.6 hours
B.62/3 hours
C.7 hours
D.71/2 hours
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Answer:
C. 7 hrs
Step-by-step explanation:
A's 1 hr work = 1/12
B's 1 hr work = 1/15
C's 1 hr work = 1/20
(A+B)'s 1 hr work = (1/12)+ (1/15) = 3/20
(A+C)'s 1 hr work = (1/12) + (1/20) = 2/15
Now work completed in first two hrs = (3/20) + (2/15) = 17/60
Now work completed in next two hrs = 2 * (17/60) = 17/30
Now total Time taken = 4 hrs
Now work completed in next two hrs = 2 * (17/30) = 17/15
Total time taken = 6 hrs,
Now work Remaining = 1- (17/15) = -2/15
So in next one hour pipes (A+C) work will fill the tank = 2/15-2/15
= 0
So Total time take to fill the tank is 7 hrs
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