three taps a B and c can fill an empty water tank in 12 hours 16 hours and 24 hours respectively how long would the three taps take to fill the empty water tank if all of them are opened simultaneously.
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Answer:
(A+B)'s hour's work=(
12
1
+
15
1
)=
60
9
=
20
3
.
(A+C)'s hour's work =(
12
1
+
20
1
)=
60
8
=
15
2
.
Part filled in 2hrs =(
20
3+
15
2 )=
60
17
.
Part filled in 6hrs=(3×
60
17 )=
20
17
.
Remaining part =(1−
20
17)=
20
3
Noe, it is turn of A and B and
20
3
part is filled by A and B in 1 hour.
∴ Total time taken to fill the tank =(6+1)hrs =7hrs.
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