Three taps A, B, C fill a tank 20 m. After 5 minutes, turn off the tap. So now the rest of the tank A and B are filled in 40 minutes, then how much time did the single tap fill the tank for c?
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Answer:
A can fill the empty tank alone in ( 12/1 × 1 ) = 12 hours.
Step-by-step explanation:
let, ( A + B ) means a and B work together.
( A + b ) can fill an empty tank in 8 hours and after 2 hours B was stopped. That means first 2 hours A and B worked together.
( A + b ) can fill a 2/8 = 1/4 part in 2 hours.
after 2 two hours, A fill the remaining part of tank which is ( 1 - 1/4 ) = 3/4 in ( 11- 2) = 9 hours
It means A can fill ( 3/4 × 1/9 ) = 1/12 part in 1 hour.
Therefore, A can fill the empty tank alone in ( 12/1 × 1 ) = 12 hours.
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