Math, asked by amankumardas700438, 6 months ago


Three taps M, N and O are opened together. If M fills the tank in 2 hours, N fills it in 3 hours
and third tap C empty it in 6 hours. Then in how much time will they take to fill it up the tank?


Answers

Answered by nandika262008
1

Answer:

Tap A fills the tank in 3 hours

Thus it can fill 1/3 of the tank in 1 hour,

Tap B fills the tank in 6 hours.

This it can fill 1/6 of the tank in 1 hour

In how much time will the tank be filled if both the taps are opened together?

If both the tap opened together they can fill the tank

= 1/3 + 1/6

= (2 + 1)/6 in one hour

= 3/6 or 1/2 of the tank in one hour

Thus, in 2 hours both the tap can completely fill the tank.

Answer: Both the tap on opening together can completely fill the tank in 2 hours

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