Three test tubes were taken and they were labelled as I , II and III. Ethanoic acid was taken in the test tube I, aqueous solution of sodium carbonate was taken in test tube II, and an aqueous solution of sodium hydrogen carbonate was taken in test tube III. On dipping a pH paper in each of the solution the colour of the pH paper in the test tubes I,II and III respectively becomes *
orange, green, green
green, blue, blue
blue, orange, orange
orange, blue, blue
Answers
Answer:
The reaction between sodium hydrogen carbonate Solution and ethanoic acid causes evolution of Carbon dioxide.
When an acid and base reacts with each other it leads to salt formation and liberation of carbon dioxide gas due to the neutralization process.
In the given case, sodium hydrogen carbonate is base whereas ethanoic acid is acid.
Thus when these two reactants are reacted, it leads to the formation of sodium acetate (salt), carbon dioxide and water.
The chemical equation for the evolution of the gas is as follows:
As carbon dioxide doesn't supports combustion, when a burning splinter is bought near the test tube, it gets extinguished.
Explanation:
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Answer:
option d
Explanation:
ethanoic acid being weak acid will show orange colour.
Na²CO³ is made of strong base NaOH and weak acid H²CO³ so it will be basic and show blue colour.
In case NaHCO³ it will be basic as in the above process water produced has combined with Na²CO3