Question

Three times a number decreased by 5 exceeds twice the number by 1. Find the number.​

Answer 1

Answer:

Let x be the number

So, there times of the number is 3x

Wheb it decreased by 5, we get, 3x−5

ACQ,

⇒ 3x−5=2x+1

⇒ 3x−2x=1+5

⇒ x=6

Therefore, the required number is 6

Step-by-step explanation:

Hope it helps.

Answer 2

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