three times a number increased by 5 times another number is 49 but twice the second number exceeds 5 times the first number by 1 what are the numbers.
Answers
Answer:
Step-by-step explanation: let the first number be X and second number be y.
3x+5y=49__1 ×5
2y=5x+1
5x-2y=-1___2 ×3
15x+25y=245
15x-6y=-3
Subtract
31y=248
y=8
Substituting y on each 1 or 2
We get x=3
Hope it's correct
Step-by-step explanation:
Let the first number be x and second number be y.
Three times a number increased by five times another number is 49 :]
➳ 3x + 5y = 49 ............[Equation (i)]
Twice the second number exceeds five times the first number by 1 :]
➳ 2y = 5x + 1
➳ 5x - 2y = -1 ............[Equation (ii)]
Now, Multiplying equation (i) by 5 we get,
➳ 15x + 25y = 245 ...........[Equation (iii)]
Multiplying equation (ii) by 3 we get,
➳ 15x - 6y = -3 ............[Equation (iv)]
Now, substracting equation (iv) from equation (iii) we get ,
➳ 31y = 248
➳ y = 248/31
➳ y = 8
Putting value of y = 8 in equation (i) we get,
➳ 3x + 5y = 49
➳ 3x + 5(8) = 49
➳ 3x + 40 = 49
➳ 3x = 49 - 40
➳ 3x = 9
➳ x = 9/3
➳ x = 3