Question

Three times of a number added to two times of another number gives 33. When three times of the second number is subtracted from four times the other number got 10. taking the numbers as x and y form the equations and find the numbers?​

Answer 1

Answer:numbers are 7 and 5

Step-by-step explanation:

Let the two numbers be x and y.

By question,

4x+3y=43.........(1),and

3x-2y=1

.2)

Multiplying both sides of (1) by 2 we get

8x+6y=86

Multiplying both sides of (2) by 3 we

9x-6y=33

get

Now adding above two equations we get

17x=119

Therefore x=7

Putting this value of x in any of the above equations we get

3x7-2y=11

Or,21-11=27

Or,10=2y

Therefore y =5