Question

three times of sum of zeroes of cubic polynomial 2x3-kx2+7x-16 is twice the product of zeros then find the value of k​

Answer 1

Answer:

32/3

Step-by-step explanation:

According To Question

3(sum of zeroes) = 2(product of zeroes)

sum of zeroes = -b/a = -(-k)/2 = k/2

product of zeroes = -d/a = -(-16)/2= 8

inserting the values

3(k/2) = 2(8)

k= (16*2)/3 = 32/3