Question

three times of the smallest of three consecutive odd number decreased by 7 equal twice the largest one. find the number​

Answer 1

Answer:15,17 and 19

Step-by-step explanation:

Let the 3 consecutive odd numbers be (x-1), (x+1) & (x+3).

By question,

3(x-1)-7=2(x+3)

Or, 3x-3-7=2x+6

Or, 3x-2x=6+10

Or, x=16

Therefore required numbers are 15,17 and 19