Question

Three times the first of the three consecutive add integers is 3 more than twice the third integer. Find the third integer.~​

Answer 1

Answer:

Let the three consecutive odd integers be x, x+2, x+4

Three times the first of three consecutive odd integers is 3 more than twice the third.

∴ 3x=2(x+4)+3

∴ x=11

Hence, the third integer is 11+4=15.

Step-by-step explanation:

Answer 2

According to the problem statement, Three times the first of three consecutive odd integers is 3 more than twice the third i.e. To get the numbers, we have to solve this linear equation i.e. So, the value of num is 13 i.e. the second integer. First integer is num – 2 i.e. 13 – 2 = 11.