three times the first of the three consecutive odd integers is 3 more than the twice the third integer. find the third integer
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Three consecutive odd integers be x,x+2,x+4
3(x) = 2(x+4) + 3
On solving x = 11
Integers- 11,13,15
3(x) = 2(x+4) + 3
On solving x = 11
Integers- 11,13,15
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