Question

Three times the first of three consective odd intergers is 3
more than
twice the third. What is the third integers?​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

1st odd integer = 2x + 1

2nd odd integer = 2x + 3

3rd odd integer = 2x + 5

3 (2x + 1) = 3 + 2 (2x + 5)

6x + 3 = 3 + 4x + 10

6x + 3 = 4x + 10 + 3

6x + 3 = 4x + 13

6x - 4x = 13 - 3

2x = 10

x = 10 ÷ 2

x = 5

Hence, the 3rd integer = 2x + 5

= 2 × 10 + 5

= 10 + 5

= 15

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