Question

Three times the lesser of two consecutive odd integers is eleven more than two times the greater of the two integers. What are the two integers?

Answer 1

Answer:

3n = 11+2 (n+2) n= lesser number

3n = 11+2n+4. (n+2)= greater number

3n = 15+2n

3n-2n=15

n=15

15×3 =11+((15+2)×2)

the numbers are 15 and 17

plz mark me as brainliest...