Question

. Three times the smallest of three consecutive odd integers decreased by 7 equals twice the largest number. Find the numbers.

Answer 1

Answer:

$The \: three \: consecutive \: odd \: integers \: are \: 15, \: 17 \: and \: 19$

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Step-by-step explanation:

$Let \: three \: consecutive \: odd \: integers \: be \: x, \: (x + 2) \: and \: (x + 4). \\ By \: given \: conditions: \\ 3(x) - 7 = 2(x + 4) \\ 3x - 7 = 2x + 8 \\ 3x - 2x = 8 + 7 \\ x = 15 \\ Now \\ x + 2 = 15 + 2 = 17 \\ x + 4 = 15 + 4 = 19 \\ Therefore \: the \: three \: consecutive \: odd \: integers \: are \: 15, \: 17 \: and \: 19$