Question

three times the smallest of three consecutive odd numbers decreased 7 equals twice the largest one find the numbers ???​

Answer 1

Answer:

15 , 17 and 19

Step-by-step explanation:

3 times the smallest of 3 consecutive odd numbers decreased by 7 equals twice the largest one. Therefore the numbers = 15,17,19.

Answer 2

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Let odd number are

$2n +1 \\ 2n + 3 \\ 2n + 5$

Now according to question

{3(2n+1)-7} = 2{2n+5}

$6n + 3 - 7 = 4n + 10$

$2n = 14 = > n = 7$

So, numbers are 2 × 7 + 1, 2 × 7 + 3 , 2 × 7 + 5 , 15 , 17 , 19