Question

three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one find the numbers

Answer 1

Hey!!!!

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let the three consecutive odd numbers be x, x + 2 and x + 4.

Then,

=> 3x - 7 = 2(x + 4)

=> 3x - 7 = 2x + 8

=> x = 15

Thus the numbers are 15,17 and 19.

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Hope this helps ✌️

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Answer 2

hye

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Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one

let the smallest number be x

then other two numbers are

=>x +2 and x +4


here x +4 is largest

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Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one

so let us form an euqation

=> 3x - 7 = 2 (x +4)

=>3x  -7 = 2x +8

=>  3x  - 2x = 7+8

=>x = 15

the smallest number is 15
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since , the other two numbers are

=>x +2 and x +4

they are 

=>x +2                   x +4

=> 15+2                  15+4

=>17                             19

so the 3 numbers are 15,17 and 19

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hope it helps u.....