Question

Three times the smallest of three consecutive odd numbers decreased by 7 equal twice the largest one find the numbers

Answer 1

Let the numbers be x, x+2 & x+4

ATQ,
(3x-7) = 2(x+4)
3x-7 = 2x+8
3x-2x = 8+7
x=15

Thus,
No. are :
x=15
x+2=15+2=17
x+4=15+4=19

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