Question

three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one. find the numbers

Answer 1

the three consecutive odd numbers are 2n+1, 2n+ 3 and 2n+5.

(3×(2n+1))-7= 2×(2n+5)

6n+3-7= 4n+10

2n=14

n=7

So, the numbers are 15, 17, 19