Question

three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one . Find the numbers

Answer 1

let 3 consecutive odd no be x+1,x+3.x+5

ATQ

3(X+1)-7=2(X+5)

3X+3-7=2X+10

3X-4=2X=10

3X-2X=10+4

X=14

Required nos. are 15,17.19

proof

3×15-7=2×19

38=38