three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one . Find the number and explain in detail
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hєrє íѕ чσur αnѕwєr thαt чσu hαvє αѕkєd fσr :
уσυя qυєѕтισи:
Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one. Find the numbers...
αnѕwєr:
Consicutive odd (smallest) numbers be x, x+2,x+4
3x-7 be the three times of smallest numbers decreased by 7
2(x+4) be the twice the largest number
From the above we get;
3x-7 = 2(x+4)
Therfore we get;
3x-7 = 2x+8
3x-2x = 8+7
x= 15
Therefore x = 15
x=15,x+2= 15+2=17,x+4=15+4=19
Therefore the three consicutive odd numbers are 15,17 and 19
__________________
ι нσρєѕ тнιѕ ωιℓℓ нєρℓѕ уσυ ^_^
нανє α gяєαт ∂αу αнєα∂ :)
#bebrainly
•_•
hєrє íѕ чσur αnѕwєr thαt чσu hαvє αѕkєd fσr :
уσυя qυєѕтισи:
Three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one. Find the numbers...
αnѕwєr:
Consicutive odd (smallest) numbers be x, x+2,x+4
3x-7 be the three times of smallest numbers decreased by 7
2(x+4) be the twice the largest number
From the above we get;
3x-7 = 2(x+4)
Therfore we get;
3x-7 = 2x+8
3x-2x = 8+7
x= 15
Therefore x = 15
x=15,x+2= 15+2=17,x+4=15+4=19
Therefore the three consicutive odd numbers are 15,17 and 19
__________________
ι нσρєѕ тнιѕ ωιℓℓ нєρℓѕ уσυ ^_^
нανє α gяєαт ∂αу αнєα∂ :)
#bebrainly
•_•
rana1140:
thanks
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